70x^2+43x-330=0

Solution for 70x^2+43x-330=0 equation:

70x^2+43x-330=0

a = 70; b = 43; c = -330;
Δ = b2-4ac
Δ = 432-4·70·(-330)
Δ = 94249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{94249}=307$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-307}{2*70}=\frac{-350}{140}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+307}{2*70}=\frac{264}{140}
=1+31/35
$